Question

Дана функция y = x2+2x-5,найдите значение функции f(2), f (-4).

Answer 1

Ответ:

f(2)=2²+2*2-5 = 3

f(-4)= (-4)²+2*(-4) -5= 16 -8 -5=3

Answer 2

Ответ: f(2)=4+4-5=3

f(-4)=16-8-5=3. Всё просто.

Объяснение:

Answer 3

To find the values of the function f(x) = x^2 + 2x - 5 at specific points, you simply need to substitute the given x-values into the function and calculate the corresponding y-values.

1. For f(2): Substitute x = 2 into the function: f(2) = (2)^2 + 2(2) - 5 f(2) = 4 + 4 - 5 f(2) = 3

So, f(2) = 3.

2. For f(-4): Substitute x = -4 into the function: f(-4) = (-4)^2 + 2(-4) - 5 f(-4) = 16 - 8 - 5 f(-4) = 3

So, f(-4) = 3.

Therefore, the values of the function f(2) and f(-4) are both equal to 3.