Question

4. Представьте в виде произведения. 1. а2-16b2; 2) х 2 - у2 - 5х - 5у; 3) 27- х9.

Answer 1

1. а2-16b2=(а-4b)(a+4b)

2. х 2 - у2 - 5х - 5у=(x+y)(x-y)-5(x+y)=(x+y)(x-y-5)

3. 27- х9=(3-x³)(9+3x³+x^6)

Answer 2

1. a^2 - 16b^2 can be factored as (a + 4b)(a - 4b).

2. x^2 - y^2 - 5x - 5y can be factored as (x - y)(x + y) - 5(x + y), which further simplifies to (x + y)(x - y - 5).

3. 27 - x^9 cannot be further factored using simple algebraic techniques.