Question

1) 4a²b² : (2a⁴b²);​

Answer 1

Ответ:

2/x^2

Объяснение:

Во второй строчке мы разъединили дроби и сократили их:

$\frac{4a^2b^2}{2a^4b^2}\\\frac{4a^2}{2a^4} *\frac{b^2}{b^2}\\\frac{4a^2b^2}{2a^4b^2}=\frac{2}{a^2}$

Answer 2

To simplify the expression $\frac{4a^2b^2}{2a^4b^2}$, you can follow these steps:

1. Divide the coefficients: $\frac{4}{2} = 2$.
2. Divide the variables with the same base by subtracting their exponents: $a^2 / a^4 = a^{2-4} = a^{-2}$, and $b^2 / b^2 = b^{2-2} = b^0$.

Remember that any non-zero number raised to the power of 0 is 1, so $b^0 = 1$.

Putting it all together, the simplified expression is: $\frac{4a^2b^2}{2a^4b^2} = \frac{2}{a^2}$

Therefore, $\frac{4a^2b^2}{2a^4b^2}$ simplifies to $\frac{2}{a^2}$.