Question

3(m+1)(m−1)−4(2+1,5m)(1,5m−2)+6m(m−1)=31​

Answer 1

Відповідь:

Пояснення:

Answer 2

Let's simplify the given expression step by step:

1. Expand the expressions within the parentheses: 3(m + 1)(m - 1) = 3(m^2 - 1) -4(2 + 1.5m)(1.5m - 2) = -4(3 + 3m)(1.5m - 2) = -6(3 + 3m)(1.5m - 2) 6m(m - 1) = 6m^2 - 6m

2. Distribute the constants through the expressions: -6(3 + 3m)(1.5m - 2) = -9(2m^2 - 3m - 4)

3. Combine like terms within each expression: 3(m^2 - 1) - 9(2m^2 - 3m - 4) + 6m^2 - 6m = 31

4. Distribute the constants further and combine like terms: 3m^2 - 3 - 18m^2 + 27m + 36 + 6m^2 - 6m = 31

5. Combine the quadratic terms and the linear terms: -9m^2 + 21m + 27 = 31

6. Move all terms to one side to set the equation equal to zero: -9m^2 + 21m + 27 - 31 = 0

7. Combine constants: -9m^2 + 21m - 4 = 0

So, the simplified equation is: -9m^2 + 21m - 4 = 0