Question

10x²-7x+1=0 A) -9 Б) 89 В)3 Г)9

Answer 1

Ответ:

НА СПАСИБО НАЖМИ ПЖ

Объяснение:

10x²-7x+1=0

D=(-7)²-4·10·1=49-40=9

ОТВЕТ: Г)9

Answer 2

To solve the quadratic equation $10x^2 - 7x + 1 = 0$, we can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

where $a = 10$, $b = -7$, and $c = 1$.

Plugging in these values:

$x = \frac{7 \pm \sqrt{(-7)^2 - 4 \cdot 10 \cdot 1}}{2 \cdot 10}$

Simplifying under the square root:

$x = \frac{7 \pm \sqrt{49 - 40}}{20}$ $x = \frac{7 \pm \sqrt{9}}{20}$ $x = \frac{7 \pm 3}{20}$

Now we have two possible solutions:

1. $x = \frac{7 + 3}{20} = \frac{10}{20} = \frac{1}{2}$
2. $x = \frac{7 - 3}{20} = \frac{4}{20} = \frac{1}{5}$

None of the provided options (A) -9, (Б) 89, (В) 3, (Г) 9 match the solutions to the given quadratic equation $10x^2 - 7x + 1 = 0$.