Question

(9х-27)*(11х-121)*(5х+25)=0

Answer 1

(9х-27)*(11х-121)*(5х+25)=0

произведение равно 0 , когда хотя бы  один их множителей равен 0

9х-27=0  11х-121=0  5х+25=0

х=3           х=11          х= -5

Answer 2

To solve the equation (9x - 27)(11x - 121)(5x + 25) = 0, we can use the zero product property, which states that if a product of factors equals zero, then at least one of the factors must be zero. So, we can set each factor equal to zero and solve for x.

Setting the first factor equal to zero: 9x - 27 = 0 9x = 27 x = 27/9 x = 3

Setting the second factor equal to zero: 11x - 121 = 0 11x = 121 x = 121/11 x = 11

Setting the third factor equal to zero: 5x + 25 = 0 5x = -25 x = -25/5 x = -5

Therefore, the solutions to the equation (9x - 27)(11x - 121)(5x + 25) = 0 are x = 3, x = 11, and x = -5.