Question

{4x-5y=3 {2x +10y =28 Смотреть ответ Ilyazov45 Ilyazov45 Ответ: (3,4;2,12) Объяснение:

Answer 1

Looks like you've provided a system of linear equations:

Equation 1: $4x - 5y = 3$ Equation 2: $2x + 10y = 28$

You've also mentioned an answer $(3,4;2,12)$, which seems to be in a format that includes pairs of values. However, the usual way to represent a solution to a system of linear equations is in the form of an ordered pair $(x, y)$.

Let's solve this system of equations step by step to find the correct solution.

Step 1: Solve Equation 2 for $x$: $2x = 28 - 10y$ $x = \frac{28 - 10y}{2}$ $x = 14 - 5y$

Step 2: Substitute the expression for $x$ from Step 1 into Equation 1: $4x - 5y = 3$ $4(14 - 5y) - 5y = 3$ $56 - 20y - 5y = 3$ $56 - 25y = 3$ $-25y = 3 - 56$ $-25y = -53$ $y = \frac{-53}{-25}$ $y = \frac{53}{25}$

Step 3: Substitute the value of $y$ back into the expression for $x$ from Step 1: $x = 14 - 5y$ $x = 14 - 5 \cdot \frac{53}{25}$ $x = 14 - \frac{265}{25}$ $x = \frac{350 - 265}{25}$ $x = \frac{85}{25}$ $x = \frac{17}{5}$

So, the solution to the system of equations is $(x, y) = \left(\frac{17}{5}, \frac{53}{25}\right)$, which is approximately $(3.4, 2.12)$. It seems the given solution $(3,4;2,12)$ might be a typographical error, as the correct solution should be in the form of an ordered pair.