Question

1) [x-y = 2,2х - Зу = -1;​

Answer 1

Ответ:

если не видно прости....

Answer 2

It looks like you've provided a system of equations with two equations involving two variables, x and y. The equations are:

1. $x - y = 2$
2. $2x - 3y = -1$

You can solve this system of equations using various methods, such as substitution or elimination. Let's solve it using the elimination method:

First, let's multiply the first equation by 2 to match the coefficient of $x$ in the second equation: $2 \cdot (x - y) = 2 \cdot 2$ This simplifies to: $2x - 2y = 4$

Now we have the system of equations:

1. $2x - 2y = 4$
2. $2x - 3y = -1$

Subtracting the first equation from the second equation eliminates $2x$: $(2x - 3y) - (2x - 2y) = -1 - 4$ Simplifying: $-y = -5$

Now, multiply both sides by -1 to solve for $y$: $y = 5$

Now that we have the value of $y$, we can substitute it into the first equation to solve for $x$: $x - 5 = 2$ Adding 5 to both sides: $x = 7$

So, the solution to the system of equations is $x = 7$ and $y = 5$.