Question

8(2y-5)-4(3y-7)-6y=-2y-12​

Answer 1

Объяснение:

16y-40-12y+28-6y=-2y-12

-2y-12=-2y-12

y принадлежит R

Answer 2

Відповідь:

Пояснення:

Answer 3

Let's solve the equation step by step:

Given equation: 8(2y - 5) - 4(3y - 7) - 6y = -2y - 12

First, distribute the coefficients to the terms inside the parentheses:

16y - 40 - 12y + 28 - 6y = -2y - 12

Now, combine like terms on both sides of the equation:

(16y - 12y - 6y) + (-40 + 28) = -2y - 12

-2y - 12 = -2y - 12

At this point, you can see that both sides of the equation are identical. This means that the equation is an identity, which means it's true for all values of 'y'. In other words, there is no specific value of 'y' that will make the equation untrue. This also means that there are infinitely many solutions to this equation.

So, the solution to the equation is all real numbers 'y'.