Question

Решите уравнения:1) x²=-16 2) 3x²=0,48​

Answer 1

1)Корней нет

2)x=0,4 и x=-0,4

Answer 2

Ответ:

1)х=∅

2)х1=0,4 х2=-0,4

Answer 3

1. x² = -16

To solve this equation, we need to take the square root of both sides. However, there's a complication because the square root of a negative number is not a real number. Instead, we'll use the concept of complex numbers:

x² = -16

Take the square root of both sides:

√(x²) = ±√(-16)

x = ±√(-1)√(16)

x = ±4i

So, the solutions to the equation are x = 4i and x = -4i.

2. 3x² = 0.48

To solve this equation, first, divide both sides by 3:

3x²/3 = 0.48/3

x² = 0.16

Now, take the square root of both sides:

√(x²) = ±√(0.16)

x = ±0.4

So, the solutions to the equation are x = 0.4 and x = -0.4.