Question

3) -3.x + 11x + 4 = 0;​

Answer 1

Ответ:

4(2х+1)

Объяснение:

думаю правильно

Answer 2

To solve the quadratic equation -3x^2 + 11x + 4 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation:

a = -3 b = 11 c = 4

Plug these values into the formula:

x = (-11 ± √(11² - 4(-3)(4))) / (2(-3))

Now, calculate the discriminant (the value inside the square root):

Discriminant = b² - 4ac Discriminant = (11)² - 4(-3)(4) Discriminant = 121 + 48 Discriminant = 169

Now, you have:

x = (-11 ± √169) / (2(-3))

x = (-11 ± 13) / (-6)

Now, you have two possible solutions:

1. x = (-11 + 13) / (-6) = 2 / (-6) = -1/3
2. x = (-11 - 13) / (-6) = -24 / (-6) = 4

So, the solutions to the equation -3x^2 + 11x + 4 = 0 are:

x = -1/3 x = 4