Question

64z2+3=(4z+1)(16z+4).

Answer 1

Объяснение:

ответ: -1

хорошего дня!

Answer 2

To verify whether the given equation is true or not, we can start by simplifying both sides of the equation and see if they are equal. Here's how you can do it:

Given equation: 64z^2 + 3 = (4z + 1)(16z + 4)

First, expand the right side of the equation using the distributive property:

(4z + 1)(16z + 4) = 4z(16z) + 4z(4) + 1(16z) + 1(4)

Now, multiply the terms:

64z^2 + 16z^2 + 16z + 16z + 4

Combine like terms:

80z^2 + 32z + 4

Now, compare the simplified right side to the left side of the equation:

64z^2 + 3

The simplified right side is 80z^2 + 32z + 4, and the left side is 64z^2 + 3.

These two expressions are not equal, so the given equation:

64z^2 + 3 = (4z + 1)(16z + 4)

is not true for all values of z.