Question

10 (2х -7)-5 (4х -2)=-60.

Answer 1

$10 \cdot (2x-7) -5\cdot (4x-2)=-60 \\ \\ 10\cdot (2x-7)-5\cdot 2\cdot (2x-1)=-60 \ \ \ : | \ 10 \\ \\ (2x-7) -(2x-1)=-6 \\ \\ 2x-7-2x+1=-6 \\ \\ 2x-2x-7+1 =-6 \\ \\ -6=-6$

Answer 2

To solve the equation 10(2x - 7) - 5(4x - 2) = -60, you need to follow these steps:

1. Distribute the constants (10 and 5) to the terms inside the parentheses:

   10 * 2x - 10 * 7 - 5 * 4x + 5 * 2 = -60

2. Simplify each term:

   20x - 70 - 20x + 10 = -60

3. Now, combine like terms on both sides of the equation:

   20x - 20x - 70 + 10 = -60

4. Continue simplifying:

   -70 + 10 = -60

5. Combine the constants on the left side:

   -60 = -60

The equation simplifies to -60 = -60. This equation is always true, which means it's an identity. In other words, there are an infinite number of solutions for this equation because any value of x will make the equation true.