Question

6) 3x(x-2)-1=x-0,5(8+x^2) ​

Answer 1

Ответ на фотографии

Answer 2

To solve the equation 3x(x-2) - 1 = x - 0.5(8 + x^2), follow these steps:

1. Distribute and simplify on both sides of the equation:

3x(x-2) - 1 = x - 0.5(8 + x^2)

3x^2 - 6x - 1 = x - 4 - 0.5x^2

2. Move all terms to one side of the equation:

3x^2 - 0.5x^2 - 6x - x - 4 + 1 = 0

2.5x^2 - 7x - 3 = 0

3. Now, we have a quadratic equation in the form of ax^2 + bx + c = 0. To solve for x, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In your case, a = 2.5, b = -7, and c = -3. Plug these values into the quadratic formula:

x = (-(-7) ± √((-7)^2 - 4 * 2.5 * (-3))) / (2 * 2.5)

x = (7 ± √(49 + 30)) / 5

x = (7 ± √79) / 5

So, the solutions for x are:

x = (7 + √79) / 5 x = (7 - √79) / 5