Question

F(x)=x^3-5x^2+12x-33, a x0=2

Answer 1

Ответ:

Якщо щось не зрозуміло то пиши

Answer 2

It looks like you have provided a function, $f(x) = x^3 - 5x^2 + 12x - 33$, and a starting point $x_0 = 2$. It seems like you want to perform some calculations or analysis with this function, perhaps finding the value of the function at $x = 2$.

To find $f(x_0)$ when $x_0 = 2$, you simply need to substitute $x_0$ into the function:

$f(2) = 2^3 - 5(2)^2 + 12(2) - 33$

Now, calculate each term:

$f(2) = 8 - 5(4) + 24 - 33$

$f(2) = 8 - 20 + 24 - 33$

Now, add and subtract the terms:

$f(2) = (8 + 24) - (20 + 33)$

$f(2) = 32 - 53$

$f(2) = -21$

So, $f(2) = -21$. That's the value of the function at $x = 2$.