Question

7x2-22x+3=0​

Answer 1

Не знаю , может так !

Answer 2

To solve the quadratic equation 7x^2 - 22x + 3 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In your equation:

a = 7 b = -22 c = 3

Now, plug these values into the quadratic formula:

x = (-(-22) ± √((-22)² - 4 * 7 * 3)) / (2 * 7)

x = (22 ± √(484 - 84)) / 14

x = (22 ± √400) / 14

Now, calculate the two possible solutions:

1. x = (22 + √400) / 14 x = (22 + 20) / 14 x = 42 / 14 x = 3

2. x = (22 - √400) / 14 x = (22 - 20) / 14 x = 2 / 14 x = 1/7

So, the solutions to the equation 7x^2 - 22x + 3 = 0 are:

x = 3 and x = 1/7