Question

1) 2b²•(-a²b)³2) -9y•(-2/3xy²)3)21x²y²•(-4/7x)4)-0,25a²b⁴•(-8a³b)​

Answer 1

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Answer 2

Let's simplify each of the expressions:

1. $2b^2 \cdot (-a^2b)^3$

$= 2b^2 \cdot (-a^6b^3)$ (Using the power of a power rule)

$= -2a^6b^5$ (Multiplying and applying the properties of exponents)

2. $-9y \cdot \left(-\frac{2}{3}xy^2\right)^3$

$= -9y \cdot \left(-\frac{8}{27}x^3y^6\right)$ (Cubing $-\frac{2}{3}xy^2$)

$= \frac{24}{3}x^3y^7$ (Multiplying and simplifying the constants)

$= 8x^3y^7$ (Simplifying further)

3. $21x^2y^2 \cdot \left(-\frac{4}{7}x\right)$

$= -84x^3y^2$ (Multiplying and simplifying the constants)

4. $-0.25a^2b^4 \cdot (-8a^3b)$

$= 2a^5b^5$ (Multiplying and applying the properties of exponents)

If you have any further questions, please, let me know.

Answer 3

Let's simplify each of these expressions:

1. 2b² * (-a²b)³ = 2b² * (-a^2 * b)^3 = 2b² * (-a^6 * b^3) = 2 * (-2a^6 * b^5) [multiply the constants] = -4a^6b^5

2. -9y * (-2/3xy²)³ = -9y * ((-2/3xy^2)^3) = -9y * (-8/27x^3y^6) [cubing the terms inside the parentheses] = -72/27 * (yx^3y^6) [multiply the constants] = -8/3xy^7

3. 21x²y² * (-4/7x) = (21/7) * x²y² * (-4/1) [simplify the constants] = 3x²y² * (-4) [multiply the constants] = -12x²y²

4. -0.25a²b⁴ * (-8a³b) = (-0.25) * a²b⁴ * (-8a³b) = 2a²b⁴ * 8a³b [multiply the constants] = 16a^5b^5

So, the simplified expressions are:

1. -4a^6b^5
2. -8/3xy^7
3. -12x²y²
4. 16a^5b^5