Question

(x-1)(x+1)=x²-2(x-3)​

Answer 1

Ответ:

х= 3,5

Объяснение:

Решение:

х^2-1=х^2-2х+6

-1=-2х+6

2х=6+1

2х=7

х= 7/2(обыкновенной дробью) = 3,5

Answer 2

Ответ:

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Answer 3

To solve the equation $(x-1)(x+1) = x^2 - 2(x-3)$, you can start by expanding both sides of the equation and then simplifying it step by step:

$(x-1)(x+1) = x^2 - 2(x-3)$

Now, let's expand both sides:

$x^2 - 1 = x^2 - 2x + 6$

Next, we can subtract $x^2$ from both sides to simplify the equation:

$-1 = -2x + 6$

Now, subtract 6 from both sides to isolate the term with $x$ on the right side of the equation:

$-1 - 6 = -2x$

Simplify the left side:

$-7 = -2x$

Finally, divide both sides by -2 to solve for (x:

$\frac{-7}{-2} = x$

Simplify the right side:

$x = \frac{7}{2}$

So, the solution to the equation is $x = \frac{7}{2}$.