Question

2m( m-1)+(m-2) (m+2)+2m при m= -0,25

Answer 1

Ответ и объяснение:

$2m(m-1)+(m-2)(m+2)+2m=2m^2-2m+m^2-4+2m=\boxed{3m^2-4.}$

$m=-0,25 \Rightarrow 3\cdot(-0,25)^2-4=3\cdot0,0625-4=0,1875-4=\boxed{-3,8125.}$

Answer 2

To evaluate the expression $2m(m-1) + (m-2)(m+2) + 2m$ when $m = -0.25$, substitute $-0.25$ for $m$ in the expression and perform the calculations:

$2m(m-1) + (m-2)(m+2) + 2m$

$= 2(-0.25)(-0.25-1) + (-0.25-2)(-0.25+2) + 2(-0.25)$

$= 2(-0.25)(-1.25) + (-2.25)(1.75) - 0.5$

$= 0.625 + (-3.9375) - 0.5$

Now, add the numbers:

$0.625 - 3.9375 - 0.5 = -3.8125$

Therefore, $2m(m-1) + (m-2)(m+2) + 2m$ when $m = -0.25$ is $-3.8125$.