Question

(4-x)(2y+1)-(3y-2)(4x+3)-35=. если x=6,y=0​

Answer 1

Ответ:

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Объяснение:

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Answer 2

To find the value of the expression (4-x)(2y+1)-(3y-2)(4x+3)-35 when x=6 and y=0, we can substitute these values into the expression and simplify it step by step.

Let's start by substituting the values of x and y into the expression:

(4 - 6)(2 * 0 + 1) - (3 * 0 - 2)(4 * 6 + 3) - 35

Now, let's simplify the expression:

(-2)(0 + 1) - (0 - 2)(24 + 3) - 35

Next, perform the calculations inside the parentheses:

(-2)(1) - (-2)(27) - 35

Now, perform the multiplications:

-2 - (-54) - 35

To subtract a negative number, we can rewrite it as addition:

-2 + 54 - 35

Now, perform the additions:

52 - 35

Finally, subtract:

17

Therefore, when x=6 and y=0, the value of the expression (4-x)(2y+1)-(3y-2)(4x+3)-35 is 17.