Question

Митя, Витя и Лёня собирали значки. У Мити было на 7 значков больше, чем у Лёни, а у Вити было на 11 значков больше, чем у Лёни. Сколько значков было у Лёни, если всего было 48 значков? ​

Answer 1

Возьмём за х количество значков у Лёни. Составим уравнение:

х + х + 7 + х + 11 = 48

Оставим все неизвестные в правой части уравнения, а числа перенесём в левую, поменяв знак на противоположный:

3х = 48 - 11 - 7

3х = 30

х = 10 - количество значков у Лёни.

Ответ: 10 значков.

Answer 2

Problem Analysis

We are given that Mitya, Vitya, and Lenya collected badges. Mitya had 7 more badges than Lenya, and Vitya had 11 more badges than Lenya. We need to determine how many badges Lenya had if there were a total of 48 badges.

Solution

Let's assume that Lenya had x badges.

According to the given information: - Mitya had 7 more badges than Lenya, so Mitya had x + 7 badges. - Vitya had 11 more badges than Lenya, so Vitya had x + 11 badges.

The total number of badges is given as 48. Therefore, we can write the equation:

x + (x + 7) + (x + 11) = 48

Simplifying the equation:

3x + 18 = 48

Subtracting 18 from both sides:

3x = 30

Dividing both sides by 3:

x = 10

Therefore, Lenya had 10 badges.

Answer

Lenya had 10 badges if there were a total of 48 badges.