Question

Задайте формулой линейную функцию, график которой параллелен прямой у = -6х + 4 и проходит через начало координат.​

Answer 1

у=кх+b  

у параллельных прямых угловые коэфффициенты равны. т.е. угловой коэффициент этой линейной функции равен тоже 5, значит, уравнение имеет вид у=-6х+b, а т.к. график - прямая проходит через начало координат, то это график прямой пропорциональности. у =-6х  

Ответ у=-6х

Answer 2

Linear Function Parallel to the Line y = -6x + 4 and Passing through the Origin

To find a linear function that is parallel to the line y = -6x + 4 and passes through the origin, we can use the slope-intercept form of a linear equation, which is given by:

y = mx + b

where: - m is the slope of the line - b is the y-intercept of the line

Since we want the line to be parallel to the line y = -6x + 4, the slope of the new line will be the same as the slope of the given line, which is -6.

Now, let's substitute the slope and the coordinates of the origin (0,0) into the slope-intercept form:

y = -6x + b

Since the line passes through the origin, the y-intercept (b) will be 0. Therefore, the equation of the linear function parallel to the line y = -6x + 4 and passing through the origin is:

y = -6x

This equation represents a line with a slope of -6 and passing through the origin. The graph of this line will be a straight line that passes through the origin and is parallel to the line y = -6x + 4.

I hope this helps! Let me know if you have any further questions.