Question

Вынесите множитель из под знака корень: 1.V2^3*35=2.Vc^33.V5x^44.V3b^55.v300m^9Пожалуйста ответьте очень надо я вас молю​

Answer 1

Объяснение:

1. √(2^3*35)=√280=2√70

2. √c^3=√(c²*c)=с√с

3. √5x^4=√(5*x²*x²)=х²√5

4. √3b^5=√(3b⁴*b)=b²√3b

5. √300m^9=√(100*3*m⁹)=10m³√3

Answer 2

Simplifying Square Roots with Multiplication

To simplify square roots with multiplication, we can break down the expression into its prime factors and then group them in pairs. Each pair of factors can be taken out from under the square root sign as a single factor.

Let's simplify the given expressions:

1. √(2^3 * 35) - We can break down 2^3 into 2 * 2 * 2. - Now, we have √(2 * 2 * 2 * 35). - Grouping the factors in pairs, we have √(2 * 2) * √(2 * 35). - Simplifying further, we get 2√(2 * 35). - Therefore, the simplified form is 2√(70).

2. √(c^3) - Since there is no other factor inside the square root, we cannot simplify it further. - Therefore, the simplified form is √(c^3).

3. √(5x^4) - We can break down x^4 into x * x * x * x. - Now, we have √(5 * x * x * x * x). - Grouping the factors in pairs, we have √(5 * x^2) * √(x^2). - Simplifying further, we get x√5 * x. - Therefore, the simplified form is x^2√5.

4. √(3b^5) - We can break down b^5 into b * b * b * b * b. - Now, we have √(3 * b * b * b * b * b). - Grouping the factors in pairs, we have √(3 * b^2) * √(b^2 * b^2 * b). - Simplifying further, we get b√3 * b^2 * √b. - Therefore, the simplified form is b^3√3.

5. √(300m^9) - We can break down 300 into 2 * 2 * 3 * 5 * 5. - We can also break down m^9 into m * m * m * m * m * m * m * m * m. - Now, we have √(2 * 2 * 3 * 5 * 5 * m * m * m * m * m * m * m * m * m * m * m * m * m). - Grouping the factors in pairs, we have √(2 * 2) * √(3 * 5 * 5) * √(m * m * m * m * m * m * m * m * m * m * m * m * m * m * m * m). - Simplifying further, we get 2√(3 * 5 * 5) * m^4√(m * m * m * m * m * m * m * m * m). - Therefore, the simplified form is 2√(75) * m^4√(m^9).

I hope this helps! Let me know if you have any further questions.