Question

33. 14. 1)(x + 5)3 - (x + 1)3 - 4(3x2 -5) + 10x - 7; 2) (x - 3)3 - x2(x + 6) - 5x(5 - 3x) - 19x + 1;3) (y + 4)3 + (3y + 1)3 - 7y2(4y + 9) + 24y2 + 8;4) (4y - 5)3 - (4y + 5)3 - 48y(1 - 10y) + 5 - 14y2.срочно срочно​

Answer 1

Ответ:

1. =3х+15-3х-3-12х в квадрате+20+10х-7=10х+23-12х в квадрате

Объяснение: інше не розумію умову. Чи в квадраті чи 2?

Answer 2

Solving the Equations

Let's solve the given equations step by step.

1) Equation 1: - (x + 5)^3 - (x + 1)^3 - 4(3x^2 - 5) + 10x - 7 - 2) (x - 3)^3 - x^2(x + 6) - 5x(5 - 3x) - 19x + 1

2) Equation 2: - (y + 4)^3 + (3y + 1)^3 - 7y^2(4y + 9) + 24y^2 + 8

3) Equation 3: - (4y - 5)^3 - (4y + 5)^3 - 48y(1 - 10y) + 5 - 14y^2

Solution

Let's start by solving each equation one by one.