Question

СРОЧНО!! (Разложите многочленов на множетели)1) 6ab-3b2=2) ac+bc-3a-3b=

Answer 1

Ответ:

1) 3b * (2a - b)
2) (a+b)(c-3)

Объяснение:

2) ac+bc-3a-3b= c (a+b) - 3(a+b) = (a+b)(c-3)

Answer 2

Ответ:

1) 3b(2a-b)

2) (c-3)(a+b)

Объяснение:

1) вынесем за скобки 3b

получится 3b(2a-b)

2) вынесем за скобки с и -3

тогде получится с(а+b)-3(a+b)=(c-3)(a+b)

Answer 3

1. 6ab - 3b^2:

To factorize this expression, let's look for common factors among the terms. The common factor in this case is 'b':

b(6a - 3b)

Now, we can see that there is a common factor of 3 as well:

3b(2a - b)

So, the factored form of the expression 6ab - 3b^2 is 3b(2a - b).

2. ac + bc - 3a - 3b:

In this expression, there is no common factor among all the terms. However, we can group the terms in pairs and factorize them separately:

(a - 3)(c + b)

So, the factored form of the expression ac + bc - 3a - 3b is (a - 3)(c + b).