Question

Выполнить действия: 1) - 2c = 2) - - =

Answer 1

$\displaystyle\bf\\1)\\\\\frac{2c^{2} }{c-8} -2c=\frac{2c^{2} -2c\cdot(c-8)}{c-8} =\frac{2c^{2}-2c^{2} +16c }{c-8} =\frac{16c}{c-8} \\\\\\2)\\\\\frac{4}{a-c} -\frac{2}{a+c} -\frac{4c}{a^{2} -c^{2} } =\frac{4}{a-c} -\frac{2}{a+c} -\frac{4c}{(a -c)(a+c)} =\\\\\\=\frac{4\cdot(a+c)-2\cdot(a-c)-4c}{(a-c)(a+c)} =\frac{4a+4c-2a+2c-4c}{(a-c)(a+c)} =\\\\\\=\frac{2a+2c}{(a-c)(a+c)} =\frac{2(a+c)}{(a-c)(a+c)} =\frac{2}{a-c}$

Answer 2

Answer:

To perform the given actions:

1) 2c + 2 = ? 2) -2 + (-2) = ?

Let's solve each action step by step:

1) 2c + 2 = ? To find the value of 2c + 2, we need to know the value of c. Since the value of c is not provided, we cannot determine the exact result. However, we can provide the general expression for 2c + 2.

The expression 2c + 2 represents the sum of twice the value of c and 2.

2) -2 + (-2) = ? To find the value of -2 + (-2), we simply add the two given numbers.

The sum of -2 and -2 is -4.

Please note that without specific values for c, we cannot provide a numerical answer for the first action. However, we have provided the general expression for 2c + 2.