Question

= -x² - 5; 5) y = -3x² + x; 26. 1) y = x² + 2; 2) y 2) y 4) y = -4x² + x; 3) y = 3x² + 2x; 6) y = 2x² - x.​

Answer 1

Ответ:

Помоему таке слиес ть ошибка сорян

Answer 2

To find the y-values for the given x-values in each equation, we can substitute the x-values into the equations and evaluate them. Let's calculate the y-values for each equation:

1. y = x² + 2: For x = 1: y = (1)² + 2 = 1 + 2 = 3

2. y = -4x² + x: For x = 2: y = -4(2)² + 2 = -4(4) + 2 = -16 + 2 = -14

3. y = 3x² + 2x: For x = 3: y = 3(3)² + 2(3) = 3(9) + 6 = 27 + 6 = 33

4. y = -4x² + x: For x = 4: y = -4(4)² + 4 = -4(16) + 4 = -64 + 4 = -60

5. y = -3x² + x: For x = 5: y = -3(5)² + 5 = -3(25) + 5 = -75 + 5 = -70

6. y = 2x² - x: For x = 6: y = 2(6)² - 6 = 2(36) - 6 = 72 - 6 = 66

So the y-values for the given x-values in each equation are:

1. y = 3
2. y = -14
3. y = 33
4. y = -60
5. y = -70
6. y = 66