Question

1)38²-28² 47²-19² 3)181²-61² 319²-77²

Answer 1

Ответ:

Объяснение:

1)  38²-28² = (38+28)(38-28) = 66*10=660;

2)  47²-19²=(47+19)(47-19) = 66*28=1848;

3)  181²-61²=(181+61)(181-61) = 242*120=2940;

4)  319²-77²=(319+77)(319-77) = 396*242 = 95832.

Answer 2

Ответ:

1) 660

2) 1848

3)29040

4)95832

Answer 3

Let's calculate the values you provided:

1. 38² - 28²: To calculate this, we need to square each number and then subtract them. Here's the calculation: 38² = 38 * 38 = 1444 28² = 28 * 28 = 784 Now we subtract them: 1444 - 784 = 660

Therefore, 38² - 28² = 660.

2. 47² - 19²: Following the same process as before: 47² = 47 * 47 = 2209 19² = 19 * 19 = 361 Subtracting them: 2209 - 361 = 1848

So, 47² - 19² = 1848.

3. 181² - 61²: Again, we square each number and subtract them: 181² = 181 * 181 = 32761 61² = 61 * 61 = 3721 Calculating the subtraction: 32761 - 3721 = 29040

Hence, 181² - 61² = 29040.

4. 319² - 77²: Applying the same process: 319² = 319 * 319 = 101761 77² = 77 * 77 = 5929 Performing the subtraction: 101761 - 5929 = 95632

Therefore, 319² - 77² = 95632.