Question

2arccos (-1)-3arctg√3

Answer 1

$2arcCos(-1) - 3arctg \sqrt{3}= 2 \pi -3* \frac{ \pi }{3} =2 \pi - \pi = \pi$

Answer 2

2П-3П/3=3П/3=П
так, вроде

Answer 3

First, let's simplify each of the trigonometric functions:

• arccos(-1) = π
• arctg(√3) = π/3

Substituting these values, we get:

2arccos(-1)-3arctg√3 = 2π - 3(π/3) = 2π - π = π

Therefore, the final answer is π radians.