Question

(у-1)^2-(у+1)(у-7)=0

Answer 1

Вот здесь решение. Все понятно, я надеюсь (камера слабая соре за качество)

Answer 2

...............
y=-2

Answer 3

To solve the equation $(y-1)^2 - (y+1)(y-7) = 0$, we'll begin by expanding the equation:

$(y-1)^2 - (y+1)(y-7) = 0$

Expanding the squares:

$y^2 - 2y + 1 - (y^2 - 7y + y - 7) = 0$

Simplifying further:

$y^2 - 2y + 1 - (y^2 - 6y - 7) = 0$

Distributing the negative sign:

$y^2 - 2y + 1 - y^2 + 6y + 7 = 0$

Combining like terms:

$-2y + 8 = 0$

To solve for y, we isolate the variable:

$-2y = -8$

Dividing both sides by -2:

$y = 4$

So the solution to the equation $(y-1)^2 - (y+1)(y-7) = 0$ is $y = 4$.