Question

Помогите плиз 4 задания сделать срочно

Answer 1

$1) (2 \frac{1}{8}* \frac{32}{17} - \frac{19}{12} ): \frac{29}{4} =( \frac{17}{8} * \frac{32}{17} - \frac{19}{12} ): \frac{29}{4} = \frac{29}{12}* \frac{4}{29}= \frac{1}{3}.$

$2) sin \beta =- \sqrt{1- \frac{49}{625} }=- \sqrt{ \frac{576}{625} }=- \frac{24}{25}.$
$ctg \beta = \frac{cos \beta }{sin \beta } = \frac{7}{25} *(- \frac{25}{24}) =- \frac{7}{24}.$

$3) \sqrt{28}+ \frac{1}{5} \sqrt{5}( \sqrt{10}-2 \sqrt{35})=2 \sqrt{7}+ \frac{ \sqrt{10} }{ \sqrt{5} }- \frac{2 \sqrt{5}* \sqrt{7} } \sqrt{5} }=$ $2 \sqrt{7}+ \sqrt{2}-2 \sqrt{7}= \sqrt{2}.$

$4) (c^{- \frac{3}{7} }x^{-0,4})^3*c^{ \frac{2}{7} }x^{0,2}=c^{- \frac{9}{7} }x^{- \frac{12}{10} }*c^{ \frac{2}{7} }x^{ \frac{2}{10} }=c^{-1}x^{-1}= \frac{1}{cx} .$

Answer 2

I hope this helps you