Question

Коливальний контур складається з конденсатора ємністю С = 0,2 мкФ і котушки індуктивностю L = 5,07 мГн. При якому логарифмічному декременті загасання різниця потенціалів на обкладках конденсатора за час t = 1 мс змінюється в три рази? Який при цьому активний опір R контура?

Answer 1

Ответ:

Объяснение:

короче так

Answer 2

The Oscillatory Circuit and Logarithmic Decrement

A oscillatory circuit, also known as a resonant circuit, consists of an inductor and a capacitor connected in parallel or series. When an oscillatory circuit is excited, it can exhibit damped oscillations, where the amplitude of the oscillations gradually decreases over time.

The logarithmic decrement is a measure of the rate at which the amplitude of the oscillations decreases. It is defined as the natural logarithm of the ratio of the amplitude of any two successive peaks of the oscillations. Mathematically, it can be expressed as:

Logarithmic Decrement (Λ) = ln(A_n / A_{n+1})

Where A_n is the amplitude of the nth peak and A_{n+1} is the amplitude of the (n+1)th peak.

Given Parameters

In this case, we are given the following parameters for the oscillatory circuit:

- Capacitance (C) = 0.2 μF - Inductance (L) = 5.07 mH - Time (t) = 1 ms - Change in potential difference on the capacitor (ΔV) = 3 times the initial potential difference

Calculating Logarithmic Decrement

To find the logarithmic decrement, we need to know the initial potential difference on the capacitor. Unfortunately, this information is not provided in the question. Therefore, we cannot calculate the logarithmic decrement without this information.

Calculating the Active Resistance

Similarly, we cannot calculate the active resistance (R) of the circuit without knowing the logarithmic decrement. The active resistance is related to the damping in the circuit and can be calculated using the following formula:

R = 2 * sqrt(L / C) * Λ

Where R is the active resistance, L is the inductance, C is the capacitance, and Λ is the logarithmic decrement.

Since we do not have the value of the logarithmic decrement, we cannot calculate the active resistance.

In conclusion, without the value of the logarithmic decrement or the initial potential difference on the capacitor, we cannot calculate the logarithmic decrement or the active resistance of the circuit.