Question

на концах рычага действуют силы 40Н и 240Н ,расстояние от точки опоры до меньшей силы 6 см. Найдите длину рычага. но он не находится в равновесии

Answer 1

Ответ:

Дано:

F1=40H

F2=240H

L1=6см=0,06м

L-?

Решение:

L=L1+L2

F1L1=F2L2

L2=F1L1/F2=40*0,06/240=0,01м

L=0,06+0,01=0,07м=7см

Ответ:7см

Объяснение:

Answer 2

Calculation of the Length of the Lever Arm

To find the length of the lever arm, we can use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point when an object is in rotational equilibrium.

In this case, we have two forces acting on the lever arm: 40 N and 240 N. The distance from the pivot point to the smaller force is given as 6 cm.

Let's assume the length of the lever arm is represented by 'x'.

Using the principle of moments, we can set up the equation:

Clockwise moment = Anticlockwise moment

(40 N) * (x cm) = (240 N) * (6 cm)

Simplifying the equation:

40x = 240 * 6

40x = 1440

x = 1440 / 40

x = 36 cm

Therefore, the length of the lever arm is 36 cm.

Please note that the lever arm is not in equilibrium, as there is an unbalanced force acting on it.