Question

Маневровий потяг переміщається на сортувальній станції зі сталою швидкістю. Відстань в 1,2 км потяг долає за 240 с. За скільки хвилин потяг Подолає 1050 M?​

Answer 1

Ответ: 3,5мин

Объяснение:

Дано:

S1=1,2км=1200м

t1=240с

S2=1050м

---------------

t2-?

V=S1/t1=1200/240=5м/c

t2=S2/V=1050/5=210c=3,5мин

Answer 2

To calculate the time it takes for the train to cover a distance of 1050 meters, we can use the information given about its constant speed and the time it takes to cover a distance of 1.2 kilometers.

Given: - Distance covered: 1.2 km - Time taken: 240 seconds

To find the time taken to cover 1050 meters, we can set up a proportion using the given information:

1.2 km / 240 s = 1050 m / x

To solve for x (the time taken to cover 1050 meters), we can cross-multiply and solve for x:

1.2 km * x = 240 s * 1050 m

x = (240 s * 1050 m) / 1.2 km

Calculating this expression will give us the time taken in seconds. To convert it to minutes, we can divide the result by 60.

Let's calculate the time taken:

Calculation:

x = (240 s * 1050 m) / 1.2 km

x = (240 s * 1050 m) / 1200 m

x ≈ 210000 s / 1200

x ≈ 175 s

Converting to minutes:

175 s / 60 ≈ 2.92 minutes

Therefore, the train will take approximately 2.92 minutes to cover a distance of 1050 meters.