Question

Определи, на сколько градусов можно нагреть подсолнечное масло массой 148 кг при сжигании керосина массой 0,3 кг, если считать, что теплота, выделившаяся при полном сгорании керосина, целиком пошла на нагревание подсолнечного масла. Удельная теплоёмкость подсолнечного масла равна 1700 Дж/(кг·°С), удельная теплота сгорания керосина — 43 МДж/кг.

Answer 1

Ответ: 51,2°С

Объяснение:

Дано:

m=148кг

m1=0,3кг

с=1700Дж/кг°с

q=43МДж/кг

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Δt-?

Q=c*m*Δt

Q=q*m1=43*0,3=12,9МДж=12900000Дж

Δt=Q/(c*m)=12900000/(1700*148)=51,2°C

Answer 2

Calculation of Temperature Increase

To determine the temperature increase of the sunflower oil when burning kerosene, we can use the equation:

Q = mcΔT

where: - Q is the heat transferred to the sunflower oil (in joules), - m is the mass of the sunflower oil (in kilograms), - c is the specific heat capacity of the sunflower oil (in joules per kilogram per degree Celsius), and - ΔT is the change in temperature of the sunflower oil (in degrees Celsius).

We are given the following values: - Mass of sunflower oil (m) = 148 kg - Mass of kerosene (m_kerosene) = 0.3 kg - Specific heat capacity of sunflower oil (c) = 1700 J/(kg·°C) - Specific heat of combustion of kerosene (Q_kerosene) = 43 MJ/kg

First, we need to convert the specific heat of combustion of kerosene from megajoules to joules: - Specific heat of combustion of kerosene (Q_kerosene) = 43 MJ/kg = 43,000,000 J/kg

Next, we can calculate the heat transferred to the sunflower oil using the equation: - Q = m_kerosene * Q_kerosene

Substituting the given values: - Q = 0.3 kg * 43,000,000 J/kg = 12,900,000 J

Finally, we can rearrange the equation to solve for the change in temperature (ΔT): - ΔT = Q / (m * c)

Substituting the given values: - ΔT = 12,900,000 J / (148 kg * 1700 J/(kg·°C))

Calculating the result: - ΔT ≈ 0.053 °C

Therefore, the sunflower oil would increase in temperature by approximately 0.053 degrees Celsius when burning 0.3 kg of kerosene, assuming all the heat released during combustion is transferred to the oil.

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