Question

камень бросили вертикально вверх со скоростью 30 м/с . На какой высоте оказался камень через 3 секунды движения и какова была его скорость в данной точке.

Answer 1

Дано:

v₀ = 30 м/с v = v₀ - gt

t = 3c h = v₀t - gt²/2

h - ? v = 30 м/с - 9,8 м/с²·3 с ≈0 м/с

м/с

v - ? h = 30 м/с·3 с - 9,8 м/с²·9 с²/2= 45 м

Ответ: 45м

Answer 2

Calculation of the Height and Velocity of a Stone Thrown Vertically Upwards

To determine the height and velocity of a stone thrown vertically upwards, we can use the equations of motion. The given information is as follows:

- Initial velocity (u) = 30 m/s (thrown vertically upwards) - Time (t) = 3 seconds

To find the height (h) and velocity (v) of the stone at a given time, we can use the following equations:

1. The equation for height (h) at a given time (t) is given by: h = u * t - (1/2) * g * t^2 where g is the acceleration due to gravity (approximately 9.8 m/s^2).

2. The equation for velocity (v) at a given time (t) is given by: v = u - g * t

Let's calculate the height and velocity of the stone at t = 3 seconds.

Using the given values: - u = 30 m/s - t = 3 seconds - g = 9.8 m/s^2

Calculation:

1. Height (h): h = u * t - (1/2) * g * t^2 Substituting the values: h = 30 * 3 - (1/2) * 9.8 * (3^2) h = 90 - (1/2) * 9.8 * 9 h = 90 - 44.1 h ≈ 45.9 meters

Therefore, the stone reaches a height of approximately 45.9 meters after 3 seconds.

2. Velocity (v): v = u - g * t Substituting the values: v = 30 - 9.8 * 3 v = 30 - 29.4 v ≈ 0.6 m/s

Therefore, the velocity of the stone at the given time is approximately 0.6 m/s.

Conclusion:

After 3 seconds of movement, the stone reaches a height of approximately 45.9 meters and has a velocity of approximately 0.6 m/s in the upward direction.