Question

A train traveling at 54 km/h starts to decelerate at 0,3 m/s^2. How long will it take to stop? What is the stopping distance?

Answer 1

Объяснение:

54 km/h = 15m/s V=a×t

t= V/a

t=15/0,3=50S

S=at^(2)/2

S=0,3×50×50/2=37,5 m

It's all.

Answer 2

To find out how long it will take for the train to stop, we can use the equation v = u + at, where v is the final velocity (0 m/s, as the train is stopping), u is the initial velocity (54 km/h, or 15 m/s), a is the deceleration (-0.3 m/s^2), and t is the time we want to find.

Rearranging the equation to solve for t, we get: 0 = 15 + (-0.3)t -15 = -0.3t t = 50 seconds

So, it will take 50 seconds for the train to stop.

To find the stopping distance, we can use the equation s = ut + (1/2)at^2, where s is the stopping distance, u is the initial velocity, t is the time, and a is the deceleration.

Plugging in the values, we get: s = 15*50 + (1/2)(-0.3)(50^2) s = 750 - 750 s = 0 meters

So, the stopping distance is 0 meters. This means that the train will stop exactly at the point where it starts decelerating.