Question

two trains are moving towards each other at velocities of 36 km/h and 54km/h. A passenger in the first train observers that the second train passes his train in a time interval of 6 seconds. What is the length a) the second train?​

Answer 1

Відповідь:

Пояснення:

t = 6 sec, $V_{1} = 36 km/h = 10 m/sec, V{2} = 54 km/h = 15 m/sec$

$L_{2} = t*V_{s}$  the second train length formula

$V_{s} = V_{1} + V_{2}$  because of moving towards each other

$L_{2} = t*(V_{1} + V_{2} )$ the general formula

$L_{2} = 6*(10+15) = 150 (m)$  

Answer: 150 m

Answer 2

To solve this problem, we can use the relative velocity concept. The relative velocity between the two trains is the sum of their individual velocities because they are moving towards each other.

Let's convert the velocities from km/h to m/s for consistency:

Velocity of the first train = 36 km/h = (36 * 1000) m/3600 s = 10 m/s Velocity of the second train = 54 km/h = (54 * 1000) m/3600 s = 15 m/s

Now, let's assume the length of the second train is L meters.

Since the second train is passing the first train, the relative velocity between them can be used to find the length of the second train.

Relative velocity = Velocity of the first train + Velocity of the second train Relative velocity = 10 m/s + 15 m/s = 25 m/s

The passenger in the first train observes that the second train passes in a time interval of 6 seconds. We can use this information to calculate the length of the second train.

Length of the second train = Relative velocity × Time interval Length of the second train = 25 m/s × 6 s Length of the second train = 150 meters

Therefore, the length of the second train is 150 meters.