Question

5. Тіло вільно падає з висоти 450 м. На якій висоті його кінетична енергія дорівнює потенціальній енергії? Який час падіння?​

Answer 1

Ответ:

Ек=Еп

В середине 450/2=225м

Answer 2

Calculation of the Height at which the Kinetic Energy is Equal to the Potential Energy

To determine the height at which the kinetic energy is equal to the potential energy, we can equate the two energies and solve for the height.

The potential energy of an object at a certain height is given by the formula:

Potential Energy = mass * gravitational acceleration * height

The kinetic energy of an object is given by the formula:

Kinetic Energy = (1/2) * mass * velocity^2

Since the object is freely falling, we can assume that all of its potential energy is converted into kinetic energy. Therefore, we can equate the two energies:

Potential Energy = Kinetic Energy

Using the formulas mentioned above, we can write the equation as:

mass * gravitational acceleration * height = (1/2) * mass * velocity^2

The mass of the object cancels out, and we are left with:

gravitational acceleration * height = (1/2) * velocity^2

We can rearrange the equation to solve for the height:

height = (1/2) * (velocity^2 / gravitational acceleration)

To calculate the height at which the kinetic energy is equal to the potential energy, we need to know the velocity of the object. Unfortunately, the velocity is not provided in the question. Therefore, we cannot determine the exact height at which the kinetic energy is equal to the potential energy without this information.

Calculation of the Time of Fall

To calculate the time of fall, we can use the equation of motion for a freely falling object:

height = (1/2) * gravitational acceleration * time^2

Rearranging the equation to solve for time:

time = sqrt((2 * height) / gravitational acceleration)

Using the given height of 450 m and the value of gravitational acceleration (approximately 9.8 m/s^2), we can calculate the time of fall:

time = sqrt((2 * 450) / 9.8) ≈ 9.02 seconds

Therefore, the time of fall for the object from a height of 450 m is approximately 9.02 seconds.

Please note that the calculation assumes no air resistance and a constant gravitational acceleration.