Question

60 баллов срочно Автомобиль, масса которого 2 т, движется по горизонтальной дороге. На участке пути длиной 37,5 м скорость его движения увеличилась от 5 до 10 м/с. Считая движение автомобиля равноускоренным, определите силу тяги его двигателя, если коэффициент сопротивления движению равен 0,02.

Answer 1

Ответ:

Объяснение:

S=(v₁²-v₀²)/(2a) ⇒a=(v₁²-v₀²)/(2*S)=(10²-5²)/(2*37,5)=(100-25)/(2*37,5)=1м/с²

ma=F-mgk

F=m(g*k+a)=2000*(10*0,02+1)=2400 Н

Answer 2

Problem Analysis

We are given the following information: - The mass of the car is 2 tons. - The car is moving on a horizontal road. - The car's speed increases from 5 m/s to 10 m/s over a distance of 37.5 m. - The coefficient of resistance to motion is 0.02.

We need to determine the force of the car's engine.

Solution

To solve this problem, we can use the equations of motion for uniformly accelerated linear motion. The equation that relates distance, initial velocity, final velocity, acceleration, and time is:

\[v^2 = u^2 + 2as\]

Where: - v is the final velocity - u is the initial velocity - a is the acceleration - s is the distance traveled

In this case, we know the initial velocity (5 m/s), final velocity (10 m/s), and distance (37.5 m). We need to find the acceleration.

We can rearrange the equation to solve for acceleration:

\[a = (v^2 - u^2) / (2s)\]

Substituting the given values:

\[a = (10^2 - 5^2) / (2 \times 37.5)\]

Now we can calculate the acceleration.

Calculation

Let's calculate the acceleration:

\[a = (10^2 - 5^2) / (2 \times 37.5)\]

\[a = (100 - 25) / 75\]

\[a = 75 / 75\]

\[a = 1 \, \text{m/s}^2\]

The acceleration of the car is 1 m/s^2.

Force of Engine

To find the force of the car's engine, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:

\[F = ma\]

Substituting the given values:

\[F = 2 \times 1\]

Now we can calculate the force of the car's engine.

Calculation

Let's calculate the force of the car's engine:

\[F = 2 \times 1\]

\[F = 2 \, \text{N}\]

The force of the car's engine is 2 N.

Answer

The force of the car's engine is 2 N.

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