Question

В калориметре находятся лёд и вода с равными массами ті 500 г при температуре t = 0 С Какая температура t установится в калориметре после добавления в него т2 = 1 кг воды притемпературе t = 50 °С? Теплоёмкостью калориметра и тепловыми потерями пренебречь.Удельная теплоёмкость воды с 4, 2 кДж/(кг- С), удельная теплота плавления льда А 340кДж/кг.​

Answer 1

Ответ: 4,8 °C

В градусах цельсия, они переведены.

Answer 2

Problem Statement

In a calorimeter, there is an equal mass of ice and water, each weighing 500 g, at a temperature of t = 0 °C. What will be the final temperature t in the calorimeter after adding 1 kg of water at a temperature of t2 = 50 °C? The calorimeter's heat capacity and heat losses can be neglected. The specific heat capacity of water is 4.2 kJ/(kg·°C), and the specific heat of fusion for ice is 340 kJ/kg.

Solution

To find the final temperature in the calorimeter, we need to consider the heat gained by the ice, the heat gained by the water, and the heat lost by the water.

Let's calculate the heat gained by the ice first. The heat gained by the ice can be calculated using the formula:

Q_ice = m_ice * c_ice * ΔT_ice

Where: - Q_ice is the heat gained by the ice - m_ice is the mass of the ice (500 g) - c_ice is the specific heat capacity of ice (which is negligible compared to water) - ΔT_ice is the change in temperature of the ice (final temperature - initial temperature)

Since the ice is initially at 0 °C and there is no change in its temperature, the heat gained by the ice is 0.

Next, let's calculate the heat gained by the water. The heat gained by the water can be calculated using the formula:

Q_water = m_water * c_water * ΔT_water

Where: - Q_water is the heat gained by the water - m_water is the mass of the water added (1 kg) - c_water is the specific heat capacity of water (4.2 kJ/(kg·°C)) - ΔT_water is the change in temperature of the water (final temperature - initial temperature)

Since the water is initially at 50 °C and the final temperature is unknown, we can rewrite the equation as:

Q_water = m_water * c_water * (t - 50)

Finally, let's calculate the heat lost by the water. The heat lost by the water can be calculated using the formula:

Q_loss = m_water * c_water * ΔT_loss

Where: - Q_loss is the heat lost by the water - m_water is the mass of the water added (1 kg) - c_water is the specific heat capacity of water (4.2 kJ/(kg·°C)) - ΔT_loss is the change in temperature of the water due to heat loss (final temperature - initial temperature)

Since the water is initially at 50 °C and the final temperature is unknown, we can rewrite the equation as:

Q_loss = m_water * c_water * (t - 50)

Since the calorimeter is assumed to have no heat losses, the heat gained by the ice and the heat gained by the water should be equal to the heat lost by the water. Therefore, we can set up the equation:

Q_ice + Q_water = Q_loss

Substituting the values we have:

0 + (m_water * c_water * (t - 50)) = (m_water * c_water * (t - 50))

Simplifying the equation, we get:

0 = 0

This equation shows that the final temperature t can be any value, as long as the heat gained by the water is equal to the heat lost by the water. Therefore, the final temperature in the calorimeter after adding 1 kg of water at a temperature of 50 °C cannot be determined without additional information.

Please let me know if there is anything else I can help you with!