Question

Столкнулись два тела массами 245 кг и 172 кг соответственно. Первое тело в результате удара стало двигаться с ускорением 1,3 м/с². С точностью до десятых определи ускорение, с которым сразу после столкновения стало двигаться второе тело. Ответ: м/с².

Answer 1

Ответ:

a2≈1,9м/с²

Объяснение:

Тела столкнулись и приобрели ускорения

$\frac{a1}{a2} =\frac{m2}{m1}$

Из этого отношения находим  a2 = (a1*m1)/m2 = ( 245 кг* 1,3 м/с² )/172 кг =

1,851744186046512 м/с²≈1,9м/с²

Answer 2

Calculation of the acceleration of the second body after the collision

To determine the acceleration of the second body after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Therefore, we can write the equation for the conservation of momentum as:

(mass of the first body * velocity of the first body) + (mass of the second body * velocity of the second body) = (mass of the first body * final velocity of the first body) + (mass of the second body * final velocity of the second body)

In this case, the mass of the first body is 245 kg, the mass of the second body is 172 kg, and the acceleration of the first body after the collision is 1.3 m/s².

Let's assume that the initial velocity of both bodies is zero, as it is not specified in the question. Therefore, the equation becomes:

(245 kg * 0 m/s) + (172 kg * 0 m/s) = (245 kg * final velocity of the first body) + (172 kg * final velocity of the second body)

Simplifying the equation, we get:

0 = (245 kg * final velocity of the first body) + (172 kg * final velocity of the second body)

Since the initial velocities are zero, the final velocities of both bodies will be the same. Let's denote the final velocity of both bodies as v.

0 = (245 kg * v) + (172 kg * v)

Combining like terms, we have:

0 = (245 kg + 172 kg) * v

0 = 417 kg * v

To solve for v, we divide both sides of the equation by 417 kg:

0 / 417 kg = v

Therefore, the final velocity of both bodies after the collision is 0 m/s.

Since acceleration is the rate of change of velocity, and the final velocity is 0 m/s, the acceleration of the second body after the collision is also 0 m/s².

Please let me know if you have any further questions!