Question

Источник с ЭДС 2В и внутренним сопротивление 3 Ом замкнут на нагрузочное сопротивление 6 Ом. Ток какой силы течёт через нагрузочное сопротивление?

Answer 1

Ответ:

$\frac{2}{9} A$

Объяснение:

Закон Ома для полной цепи будет записываться, как:

$I =$ ε / $r + R$

Отсюда сила тока будет равняться:

$I = \frac{2}{9} A$

Answer 2

#### Calculation of Current through Load Resistance To calculate the current flowing through the load resistance, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). In this case, the voltage is the electromotive force (EMF) of 2V, and the resistance is the sum of the internal resistance (3Ω) and the load resistance (6Ω). Using the formula: **I = V / R** where: - I is the current flowing through the load resistance, - V is the electromotive force (EMF) of the source (2V), - R is the total resistance (internal resistance + load resistance). Substituting the given values: **I = 2V / (3Ω + 6Ω)** Simplifying the expression: **I = 2V / 9Ω** Therefore, the current flowing through the load resistance is **I = 2/9 A**. Please note that the calculation assumes an ideal voltage source with no internal resistance. In reality, the internal resistance of the source can affect the current flowing through the load resistance.