Question

В процессе альфа распада из радиоактивного ядра вылетает ядро гелия, как при этом изменяется массовое, зарядовое число, и кол-во нейтронов? Для каждой величины выберите характер изменения  1.Увеличилось2. Уменьшилось 3.Не изменилось+ Рассчитать энергию связи 3 Н 1 (3 перед водородом на верху, 1 внизу).Помогите пожалуйста! 

Answer 1

Эххх
Массовое, протонное и зарядные числа уменьшаются согласно закону сохранения заряда и массы.
2) тритий..
значииит разность масс*931,5 и получаем: 7.95501 МэВ

Answer 2

Alpha Decay and Changes in Mass and Charge Numbers

During alpha decay, a radioactive nucleus emits an alpha particle, which consists of two protons and two neutrons. This emission causes changes in the mass number and charge number of the nucleus.

1. Mass Number (A): The mass number represents the total number of protons and neutrons in the nucleus. When an alpha particle is emitted, the mass number of the parent nucleus decreases by 4, as the alpha particle carries away two protons and two neutrons. Therefore, the mass number decreases by 4 during alpha decay.

2. Charge Number (Z): The charge number represents the number of protons in the nucleus. Since an alpha particle consists of two protons, the charge number of the parent nucleus decreases by 2 when an alpha particle is emitted. Therefore, the charge number decreases by 2 during alpha decay.

3. Number of Neutrons (N): The number of neutrons in the nucleus is equal to the difference between the mass number and the charge number (N = A - Z). As the mass number decreases by 4 and the charge number decreases by 2 during alpha decay, the number of neutrons remains the same.

To summarize the changes during alpha decay: - Mass number (A) decreases by 4. - Charge number (Z) decreases by 2. - Number of neutrons (N) remains the same.

Calculation of Binding Energy

The binding energy of a nucleus represents the energy required to completely separate its nucleons (protons and neutrons). The binding energy per nucleon is a measure of the stability of the nucleus.

To calculate the binding energy of a nucleus, you need to know the mass defect (Δm) and the speed of light (c). The formula for calculating the binding energy (E) is:

E = Δm * c^2

The mass defect (Δm) is the difference between the mass of the nucleus and the sum of the masses of its individual protons and neutrons. The speed of light (c) is approximately 3 x 10^8 meters per second.

For the given example, we have: - Mass of the nucleus = 3N1 - Mass of one hydrogen atom (proton) = 1 - Mass defect (Δm) = (Mass of the nucleus) - (Mass of one hydrogen atom)

Let's calculate the binding energy using the given values: - Mass of the nucleus = 3N1 - Mass of one hydrogen atom (proton) = 1

The mass defect (Δm) is given by: Δm = (Mass of the nucleus) - (Mass of one hydrogen atom) = (3N1) - 1

Finally, the binding energy (E) can be calculated using the formula mentioned above.

Please provide the value of N1 to proceed with the calculation.