Question

Спусковую пружину игрушечного пистолета сжали на 5 см при вышлите шарик моссой 20 г приобрёл скорость м/с Расчитаите жостко ть пружины​

Answer 1

Ответ:Дано:

h - 5см

m - 20г

ри сжатии пружины она обладает потенциальной энергией , а когда отпускаем она переходит в кинетическую энергию шарика :

Wп=Wk

kx^2/2=mv^2/2

kx^2=mv^2

k=mv^2/x^2

k=0,02*16/0,05^2=128 Н/m

Объяснение:

Answer 2

Calculation of the Spring Constant

To calculate the spring constant of the toy gun's trigger spring, we need to use the given information about the compression distance and the mass of the ball.

The formula to calculate the spring constant is:

F = k * x

Where: - F is the force applied to the spring (in Newtons) - k is the spring constant (in Newtons per meter) - x is the compression distance of the spring (in meters)

In this case, the force applied to the spring is the weight of the ball, which can be calculated using the formula:

F = m * g

Where: - m is the mass of the ball (in kilograms) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Given that the mass of the ball is 20 g (0.02 kg) and it was launched with a velocity of 20 m/s, we can calculate the force applied to the spring:

F = 0.02 kg * 9.8 m/s^2 = 0.196 N Now, we can rearrange the formula to solve for the spring constant:

k = F / x

Given that the spring was compressed by 5 cm (0.05 m), we can substitute the values into the formula:

k = 0.196 N / 0.05 m = 3.92 N/m

Therefore, the spring constant of the toy gun's trigger spring is approximately 3.92 N/m.

Please note that this calculation assumes a linear relationship between the compression distance and the force applied to the spring. In reality, the relationship may not be perfectly linear, especially for toy gun springs.