Question

Поезд,подходя к станции,затормозил и остановился через 5 мин. От момента торможения до остановки он прошёл расстояние 2 км. Определить скорость поезда в начале торможения и ускорения

Answer 1

$s = \frac{a {t}^{2} }{2} \\ a = \frac{2s}{ {t}^{2} } = \frac{2 \times 2000}{ {5 \times 60}^{2} } = \frac{2}{45} \\ v = at = \frac{2 \times 5 \times 60}{45} = 13 \frac{1}{3}$

Answer 2

Calculation of Train Speed

To determine the speed of the train at the beginning of braking and during acceleration, we can use the given information.

Given: - The train came to a stop 5 minutes after braking. - The train traveled a distance of 2 km from the moment of braking to the stop.

To calculate the speed of the train, we need to convert the time and distance into consistent units. Let's convert the time from minutes to hours and the distance from kilometers to meters.

1. Convert time: - 5 minutes = 5/60 hours = 1/12 hours

2. Convert distance: - 2 km = 2,000 meters

Now we can calculate the speed using the formula:

Speed = Distance / Time

Let's substitute the values:

Speed = 2,000 meters / (1/12 hours)

Simplifying the expression:

Speed = 2,000 meters * 12 hours

Speed = 24,000 meters per hour

Therefore, the speed of the train at the beginning of braking and during acceleration is 24,000 meters per hour.

Please note that this calculation assumes a constant speed during acceleration and braking, which may not be the case in real-world scenarios.