Question

F1=300H t1=5c F2=100H t2=?

Answer 1

300-5
100-х
х=1.6

F1/t1=F2/t2
t2=(100×5)/300=1.6

Ответ: 1.6с

Answer 2

To solve for t2, we can use the formula for the inductive reactance of an inductor:

X = 2πfL

where: X is the inductive reactance (measured in ohms) f is the frequency of the AC current (measured in hertz) L is the inductance of the inductor (measured in henrys)

First, let's find the inductive reactance (X1) for the first inductor with inductance (F1) of 300H and frequency (t1) of 5Hz:

X1 = 2π * 300H * 5Hz X1 = 3000π ohms ≈ 9424.78 ohms

Next, let's use the same formula to find the inductive reactance (X2) for the second inductor with inductance (F2) of 100H:

X2 = 2π * 100H * t2

Now, we can equate the two inductive reactances since they are in series in an AC circuit:

X1 = X2

3000π = 2π * 100H * t2

Now, solve for t2:

t2 = 3000π / (2π * 100H) t2 = 30H

So, t2 is 30H.