Question

Т1=27°с т2=42°с м1=4кг м2=7кг Т=?

Answer 1

Если это задача на смешивание жидкостей с разными температурами и нахождение температуры смеси, то:

Q1=Q2

c*m1*(t-t1)=c*m2*(t2-t)

4t-4*27=7*42-7t

11t=7*42+4*27

11t=402

t=36,5°C  -  это ответ.

Answer 2

To solve this problem, we can use the principle of energy conservation in a calorimetry system. When two substances at different temperatures are mixed, the total heat gained by one substance is equal to the total heat lost by the other substance.

Let's denote: T1 = initial temperature of substance 1 = 27°C T2 = initial temperature of substance 2 = 42°C m1 = mass of substance 1 = 4 kg m2 = mass of substance 2 = 7 kg T = final temperature of the mixture (to be determined)

We can use the formula:

m1 * c1 * (T - T1) = m2 * c2 * (T2 - T)

Where: c1 and c2 are the specific heat capacities of substances 1 and 2, respectively.

To proceed, we need to know the specific heat capacities of the substances involved. Could you provide the specific heat capacities (in J/(kg·°C)) for substances 1 and 2?