Question

Определи модуль центростремительного ускорения тела, которое равномерно движется по окружности с радиусом 0,59 м. Период обращения равен 2 с. (Ответ округли до сотых долей.) ​

Answer 1

Ответ:

5,82 м/с²

Объяснение:

R=0.59 м    T=20 c    a=?

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a=ω²*R=(2*π/T)²*R=(2*3.14/2)²*0.59≈5.82 м/с²

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Answer 2

Module of Centripetal Acceleration

The module of centripetal acceleration of a body moving uniformly in a circle can be determined using the formula:

a = v^2 / r

Where: - a is the centripetal acceleration - v is the velocity of the body - r is the radius of the circle

In this case, the body is moving uniformly in a circle with a radius of 0.59 m and a period of 2 s. To find the velocity, we can use the formula:

v = 2πr / T

Where: - v is the velocity - r is the radius of the circle - T is the period of revolution

Substituting the given values, we have:

v = 2π(0.59) / 2

Calculating this, we find:

v ≈ 1.85 m/s

Now, we can substitute this value of velocity into the formula for centripetal acceleration:

a = (1.85)^2 / 0.59

Calculating this, we find:

a ≈ 5.79 m/s^2

Therefore, the module of the centripetal acceleration of the body is approximately 5.79 m/s^2.