Question

Машина двигалась по окружности с постоянной скоростью. В точке A машина встретилась с мотоциклом, который двигался равноускоренно по диаметру AB. В точке A скорости машины и мотоцикла были равны. Машина, пройдя полкруга, встретилась с мотоциклом в точке B. Определи отношение модулей ускорения машины и мотоцикла и путь, если радиус окружности равен 249 м. Не могу понять одного факта: если машина двигалась с ПОСТОЯННОЙ скоростью, то у неё должно быть ускорение равно нулю и, как следствие, отношение тоже должно быть равно нулю, разве нет?

Answer 1

Ответ: a1/a2=4,32 м/с2 s1=781,86 м

Объяснение: ускорение - это отношение ИЗМЕНЕНИЯ скорости к промежутку времени, в течение которого это изменение совершено. верно, скорость постоянна по модулю, но ее направление при движении по окружности постоянно меняется, значит ускорение не может быть равно нулю.

Answer 2

Situation and Given Information

In this scenario, a car is moving in a circular path with a constant speed. At point A, the car encounters a motorcycle that is moving with uniform acceleration along the diameter AB. At point A, the speeds of the car and the motorcycle are equal. After completing half a circle, the car meets the motorcycle again at point B. We need to determine the ratio of the accelerations of the car and the motorcycle, as well as the distance traveled, given that the radius of the circle is 249 m.

Analysis

To solve this problem, we need to consider the motion of both the car and the motorcycle. Let's break down the problem step by step.

1. At point A, the car and the motorcycle have the same speed. This means that the centripetal acceleration of the car is equal to the tangential acceleration of the motorcycle along the diameter AB. Since the car is moving in a circular path with constant speed, its acceleration is directed towards the center of the circle and has a magnitude of zero. On the other hand, the motorcycle is moving with uniform acceleration along the diameter AB, so its acceleration is non-zero.

2. After completing half a circle, the car meets the motorcycle again at point B. At this point, the car has traveled a distance equal to half the circumference of the circle, while the motorcycle has traveled along the diameter AB. We can use the formulas for the circumference and diameter of a circle to calculate the distances traveled by the car and the motorcycle.

Calculation

Let's calculate the ratio of the accelerations of the car and the motorcycle first.

1. The acceleration of the car is zero, so the ratio of the accelerations is 0.

Next, let's calculate the distance traveled by the car and the motorcycle.

1. The circumference of a circle is given by the formula: C = 2πr, where r is the radius of the circle. In this case, the radius is given as 249 m. Therefore, the circumference of the circle is: C = 2π(249) = 1566 m.

2. The distance traveled by the car is half the circumference of the circle, since it completes half a circle. Therefore, the distance traveled by the car is: d_car = 0.5 * 1566 = 783 m.

3. The distance traveled by the motorcycle is equal to the length of the diameter AB. The length of a diameter is equal to twice the radius of the circle. Therefore, the distance traveled by the motorcycle is: d_motorcycle = 2 * 249 = 498 m.

Answer

Based on the given information and calculations, we can conclude the following:

- The ratio of the accelerations of the car and the motorcycle is 0. - The distance traveled by the car is 783 m. - The distance traveled by the motorcycle is 498 m.

Please let me know if there's anything else I can help you with!